16cos^4(x)-12cos^2(x)+1=0

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Solution for 16cos^4(x)-12cos^2(x)+1=0 equation:


Simplifying
16cos4(x) + -12cos2(x) + 1 = 0

Multiply cos4 * x
16cos4x + -12cos2(x) + 1 = 0

Multiply cos2 * x
16cos4x + -12cos2x + 1 = 0

Reorder the terms:
1 + -12cos2x + 16cos4x = 0

Solving
1 + -12cos2x + 16cos4x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -12cos2x + -1 + 16cos4x = 0 + -1

Reorder the terms:
1 + -1 + -12cos2x + 16cos4x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -12cos2x + 16cos4x = 0 + -1
-12cos2x + 16cos4x = 0 + -1

Combine like terms: 0 + -1 = -1
-12cos2x + 16cos4x = -1

Reorder the terms:
1 + -12cos2x + 16cos4x = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -12cos2x + 16cos4x = 0

The solution to this equation could not be determined.

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